Тригонометрия 1) sin3x=-√2/2 2) cos x/5 = - √3/2 - вопрос №9139681132225323231 от kjhgfffdpavel 04.02.2021 20:38

Question

Алгебра: Тригонометрия 1) sin3x=-√2/2 2) cos x/5 = - √3/2 3) tg (2x - п/3) = 1

kjhgfffdpavel · Answer

1.) sin3x = -√2/23x = (-1)^n+1 * arcsin√2/2 + pi*n3x = (-1)^n+1 * pi/4 + pi*nx = (-1)^n+1 * pi/12 + pi*n/32.) cos(x/5) = -√3/2x/5 = +-arccos√3/2 + 2pi*nx = +-5pi/6 + 10pi*n3.) tg(2x - pi/3) =12x - pi/3 = arctg1 + pi*n2x = pi/4 + pi/3 + pi*n2x = 7pi/12 + pi*nx = 7pi/24 + pi*n/2...