Решите уравнения: 8x(1++3)(4x-3)=2 (8-9x)x=-40+(6-3x)(6+3x) (x-6)²-x(x+8)=2 16x(2-x)+(4x-5)²=1 9x²-1-(3x-2)²=0 (4x-3)(3+4x)-2x(8x-1)=0

1) (8+16х) - (16х^2-9) = 2
8х+16х^2-16х^2+9 = 2
8х = -7
х = -7/8

2) 8х-9х^2 = -40+(36-9х^2)
-9х^2+9х^2+8х = -40+36
8х = -4
х= -1/2

3) (х^2-12х+36)-(х^2+8х) = 2
х^2-12х+36-х^2-8х = 2
-20х = 2-36
х = -34/-20