1) log3 56+2log2 12-log2 63 2)log4 (2x-3)=2 3)log1/2 - вопрос №8325889135622122632423231212112 от archakova65 23.11.2022 22:50

Question

Алгебра: 1) log3 56+2log2 12-log2 63 2)log4 (2x-3)=2 3)log1/2 x+log1/2 (x-1) log1/2 6

archakova65 · Answer

2) лог4 (2х-3)=2    лог4 (2х-3)=лог4 (16)     2х-3=16     2х=19      х=9,5...

1) log3 56+2log2 12-log2 63 2)log4 (2x-3)=2 3)log1/2 x+log1/2 (x-1)> log1/2 6