Sin п/3 + 2cos п/4 - ctg^2 3п/4 + tg п/6 + sin 3п/2 - вопрос №8298732324234632 от Машасом1442 21.05.2021 11:49

Question

Алгебра: Sin п/3 + 2cos п/4 - ctg^2 3п/4 + tg п/6 + sin 3п/2

Машасом1442 · Answer

Sin(π/3)=sin(60°)=√3/2.cos(π/4)=cos(45°)=√2/2.ctg²(3π/4)=ctg²(135°)=ctg²(π/2+45°)=tg²(45°=1.tg(π/6)=tg(30°)=√3/3.sin(3π/2)=sin(270°)=sin(180°+90°)=-sin(90°)=1.√3/2+√2-1+√3/3-1=5√3/6+√2-2....