Решите уравнения (5x-1)²-16x²=0 (x+3)²+(x-4)²=2(4-x)(x+3) - вопрос №77599115116034243 от hzzzkzn99 05.10.2021 04:24

Question

Алгебра: Решите уравнения (5x-1)²-16x²=0 (x+3)²+(x-4)²=2(4-x)(x+3)

hzzzkzn99 · Answer

(5x - 1)^2 - 16x^2 = 0(5x - 1 - 4x)(5x - 1 + 4x) = 0(x - 1)(9x - 1) = 0x - 1 = 0x = 19x - 1 = 09x = 1x = 1/9x^2 + 6x + 9 + x^2 - 8x + 16 = 2(4x + 12 - x^2 - 3x)2x^2 - 2x + 25 = 2(x + 12 - x^2)2x^2 - 2x + 25 = 2x + 24 - 2x^24x^2 - 4x + 1 = 0 (2x - 1)^2 = 02x - 1 = 02x = 1x = 1/2 = 0,5...