51²-41²= 63²-53²= 117²-17²= 164²-64²= 125²-25²= - вопрос №73472515141635311717164641252514863763811977 от sherkesovna82 04.03.2020 05:43

Question

Алгебра: 51²-41²= 63²-53²= 117²-17²= 164²-64²= 125²-25²= 14²-86²= 37²-63²= 81²-19²= 77²-23²= 68²-32²= 55²-53²= 41²-21²= 35²-55²= 22²-42²=

sherkesovna82 · Answer

51²-41²=(51-41)*(51+41)=10*92=92063²-53²=(63-53)*(63+53)=10*116=1160117²-17²=(117-17)*(117+17)=100*134=13400164²-64²=(164-64)*(164+64)=100*228=2280125²-25²=(125-25)*(125+25)=100*150=1500014²-86²=(14-86)*(14+86)=(-72)*100=-720037²-63²=(37-63)*(37+63)=(-26)*100=-260081²-19²=(81-19)*(81+19)=62*100=620077²-23²=(77-23)*(77+23)=54*100=540068²-32²=(68-32)*(68+32)=36*100=360055²-53²=(55-53)*(55+53)=2*108=21641²-21²=(41-21)*(41+21)=20*62=124035²-55²=(35-55)*(35+55)=(-20)*90=-180022²-42²=(22-42)*(22+42)=(-20)*64=-1280...