(4x-3)(4x+-1)^2=3x 16с^2-49=0 решите уравнение,,заранее ))

(4x-3)(4x+3)-(4x-1)^2=3x 

16x^2-9-(16x^2-8x+1)=3x

16x^2-9-16x^2+8x-1=3x

-10+8x=3x

8x-3x=10

5x=10

x=2

№2

16c^2-49=0

16c^2=49

c^2=49/16

x=(+-(7/4))

x1=7/4

x2=-(7/4)