Решите уравнние: 1)(x-3)^2-(x+1)^2=12 2)(3x-2)^2+(1-3x)(3x+2)=36 3)x(x-2)(x-3)=8+x(x-2,5)^2 4)(6x-1)^2-(5x+2)(6x+5)=6(x-1)^2-37x 5)(2x-1)(2x+1)=2(x-3)^2+x(2x-3)

1)(x-3)²-(x+1)²=12
х²-6х+9-(х²+2х+1)=12
х²-6х+9-х²-2х-1=12
-6х-2х+9-1=12
-8х=12-8
-8х=4
х= -1/2