2x^2-3x-5=0 2x^2-3x-2=0. 2x^2+5x-3=0 - вопрос №6811492223502232022530 от sushenkop08wf4 23.04.2023 23:02

Question

Алгебра: 2x^2-3x-5=0 2x^2-3x-2=0. 2x^2+5x-3=0

sushenkop08wf4 · Answer

2x² - 3x - 5 = 0D = 9 + 5•2•4 = 49 = 7²x1 = (3 + 7)/4 = 2,5x2 = (3 - 7)/4 = -1 2x² - 3x - 2 = 0D = 9 + 2•2•4 = 25 = 5²x1 = (3 + 5)/4 = 2x2 = (3 - 5)/4 = -1/22x² + 5x - 3 = 0D = 25 + 3•2•4 = 49 = 7²x1 = (-5 + 7)/4 = 1/2x2 = (-5 - 7)/4 = -3....