Решите (0.16a^{2} - 0.5ab + rac[25]{16}b^{2})(0.4a+1.25b) - вопрос №669076401620525162041251016 от dogparrker 17.03.2022 15:35

Question

Алгебра: Решите (0.16a^{2} - 0.5ab + rac[25]{16}b^{2})(0.4a+1.25b) при a=10 b=1.6

dogparrker · Answer

(0,16*100-0,5*10*1,6+25/16*2,56)*(0,4*10+1,25*1,6)=720,16*100=160,5*10*1,6=825/16*2,56=25*0,16=416-8+4=120,4*10=41,25*1,6=24+2=612*6=72...

Решите (0.16a^{2} - 0.5ab + \frac[25]{16}b^{2})(0.4a+1.25b) при a=10 b=1.6