Вычислить: a) 2^6*(2^3)^5/2^18; б) 4^7*16/(4^2)^4; - вопрос №62572052623521847164243112796 от Alakey11 13.02.2022 23:14

Question

Алгебра: Вычислить: a) 2^6*(2^3)^5/2^18; б) 4^7*16/(4^2)^4; в)3^11*27/9^6;

Alakey11 · Answer

[ 2⁶* (2³)⁵ ] / 2¹⁸ = [ 2⁶ * 2 ³*⁵ ] / 2¹⁸ = 2⁶⁺¹⁵ / 2¹⁸ = 2²¹⁻¹⁸ =2³= 8

[ 4⁷ *16 ] / [ ( 4²)⁴ ] = [ 4⁷ * 4² ] / 4⁸ = 4⁹/ 4⁸ = 4⁹⁻⁸ = 4¹ =4

[ 3¹¹ * 27 ] / 9⁶ = [ 3¹¹ *3³ ] / [ (3²)⁶ ] = 3¹⁴ / 3¹² = 3 ¹⁴⁻¹² =3² = 9