A) 6a^4b/18a^2b^3 б) a^3-3a^2b/a^2-9b^2 в)x^2+4x+4/2x^2-8 - вопрос №6153000641823332292244228 от muamy 17.11.2022 01:42

Question

Алгебра: A) 6a^4b/18a^2b^3 б) a^3-3a^2b/a^2-9b^2 в)x^2+4x+4/2x^2-8 сократите .. надо,для самостоятельной..

muamy · Answer

Решениеa) 6a^4b/18a^2b^3= a² / (3b²)б) a^3-3a^2b/a^2-9b^2 = [a² (a - 3b)] / [(a - 3b)*(a + 3b)] = a² / (a + 3b)в)x^2+4x+4/2x^2-8 = [(x + 2)²] / [2*(x² - 4)] =  [(x + 2)²] / [2*(x - 2)*(x + 2)] == (x + 2) / [2*(x - 2)]...