Решите 5/x-3 - x-2/x²-9 + x-1/2x+6 - вопрос №59268495329126 от МухаВж 24.03.2021 22:08

Question

Алгебра: Решите 5/x-3 - x-2/x²-9 + x-1/2x+6

МухаВж · Answer

1. 1x^2 -5x +4 =0D = b^2 - 4ac = (-5)^2 - 4*1*4 = 9x1 = 5 + 3 /2 = 8/2 =4x2 = 5 -3 /2 = 2/2 = 12. x^2 -3x-10 =0D = (-3)^2 + 4*1*(-10) = 49x1=3+7 / 2 = 10/2 = 5x2=3-7 /2 = -4/2=-23. 2x^2+ 3x-5=0D= (2)^2 + 4*3*(-5) = 64x1=-3+8 /4 = -4/4 = -1x2=-3-8 /4 =-11/4 = -2,754. 5x^2-7x-6=0D=(2)^2 + 4*5*(-6) = 169x1=-7+13 /10=6/10=0,6x2=-7-13 /10=-20/10=-2...