Sin(3x/2 + п/12) < корень 2/2 !

Решение
Sin(3x/2 + π/12) < √2/2
- π - arcsin(√2/2) + 2πk < 3x/2 + π/12 < arcsin(√2/2) + 2πk, k ∈ Z
- π - π/4 + 2πk < 3x/2 + π/12 < π/4 + 2πk, k ∈ Z
- 5π/4 + 2πk < 3x/2  < π/4 + 2πk, k ∈ Z
- 5π/4 - π/12  + 2πk < 3x/2  <  π/4 - π/12 + 2πk, k ∈ Z
- 4π/3 + 2πk < 3x/2  < π/6 + 2πk, k ∈ Z
- 8π/3 + 4πk < 3x  < π/3 + 4πk, k ∈ Z
- 8π/9 + 4πk/3 < x  < π/9 + 4πk/3, k ∈ Z