3x^4 - 12x^2 = 0 0,7x^2 + 8x = 0 2x^2 + rac{3}{4} - вопрос №54147433412200728022340 от kseniazorina14 31.05.2022 20:10

Question

Алгебра: 3x^4 - 12x^2 = 0 0,7x^2 + 8x = 0 2x^2 + rac{3}{4} x = 0

kseniazorina14 · Answer

1. 3x²(x² -4) =03x² =0, x=0x² -4=0, (x -2)(x +2)=0x -2=0, x=2x +2=0, x= -2отв. x=0, x= -2, x=22. x(0.7x +8) =0x=00.7x +8 =00.7x= -8x= -8/0.7 (0.7=7/10)x= -8 : 7/10x= -8*10/7x= -80/7x= -11 3/7 (одиннадцать целых три седьмых) отв. x=0, x= -11 3/7...

3x^4 - 12x^2 = 0 0,7x^2 + 8x = 0 2x^2 + \frac{3}{4} x = 0