1)-7x^2+52x-85=0 2)x^2+x-12=0 3)-x^2+2x+24=0 4)x^2-12x+36=0 - вопрос №531405817252850221203222404212360 от Apple019 02.11.2022 23:29

Question

Алгебра: 1)-7x^2+52x-85=0 2)x^2+x-12=0 3)-x^2+2x+24=0 4)x^2-12x+36=0

Apple019 · Answer

- 7х²+52х-85=0D/4=26²-7*85=81=+-9²х₁= (- 26-9)/ -7=35/7=5х₂=( -26+9)/ -7=17/7=2 3/7х²+х-12=0D=1+12*4=25=+-5²х₁= -1+1/2=0/2=0х₂= -1-1/2= - 1- х²+2х+24=0D/4=1+24=25=+-5²х₁= -1-5=-6х₂= -1+5=4х²-12х+36=0D/4=36-36=0х₁=х₂=6...