(х+2)^4-4 (х+2)^2-5=0 решите уравнение - вопрос №51836312442250 от aziret31101 12.02.2021 17:01

Question

Алгебра: (х+2)^4-4 (х+2)^2-5=0 решите уравнение

aziret31101 · Answer

(x + 2)^2( (x + 2)^2 - 4 - 5) = 0(x + 2)^2( x^2 + 4x + 4 - 4 - 5) = 0(x + 2)^2( x^2 + 4x - 5) = 0(x+ 2)(x + 2)(x^2 + 4x - 5) =0x + 2 = 0x = - 2x^2 + 4x - 5 = 0D = b^2 - 4ac = 16 + 20 = 36 = 6^2x1 = ( - 4 + 6) / 2 = 1x2 = ( - 4 - 6) / 2 = - 5ответ: x 1 = 1, x2 = - 5, x3 = - 2...