Sin(-385°)*sin(555°)-sin(-295°)*sin(165°)-cos(-1050°)= - вопрос №49170993855552951651050 от anas20041006 30.03.2020 22:58

Question

Алгебра: Sin(-385°)*sin(555°)-sin(-295°)*sin(165°)-cos(-1050°)=

anas20041006 · Answer

= -Sin385°*Sin555° +Sin295°*Sin165°-Cos1050°== -Sin(360°+25°)*Sin(540°+15°)+Sin(270°+25°)*Sin(180°-15°) - Cos(1080° - 30°)== Sin25°*Sin15° -Sin25°*Sin15° - Cos30°= -Cos30°= -...