Решите уравнение: (3х – 1)(х+ 3) + 1 = х(1 + 6х)

(3x - 1)(x + 3) + 1 = x(1 + 6x)
3x² + 9x - x - 3 + 1 = x + 6x²
3x² - 6x² + 8x - x - 2 = 0
- 3x² + 7x - 2 = 0
3x² - 7x + 2 = 0
D = b² - 4ac = 49 - 4 × 3 × 2 = 49 - 24 = 25 = 5²
x1 = ( 7 + 5) / 6 = 2
x2 = ( 7 - 5) / 6 = 2/6 = 1/3