1.x^5+x^4-6x^3-6x^2+8x+8=0 2.x^5-3x^3+x^2-3=0 - вопрос №461835915463628802533230 от natashenkagrekova357 07.11.2020 23:55

Question

Алгебра: 1.x^5+x^4-6x^3-6x^2+8x+8=0 2.x^5-3x^3+x^2-3=0

natashenkagrekova357 · Answer

x^5+x^4-6x^3-6x^2+8x+8=0x^4(x+1) - 6x^2(x+1)+8(x+1)=0(x+1)(x^4-6x^2+8)=0x + 1 = 0 x1 = -1x^4 - 6x^2 + 8 = 0t=x^2 0x^2-6t+8=0D= 36 - 32  = 4 √4=2t1=(6+2)/2=8/2=4t2=(6-2)/2=4/2=2x2;3=+-√4=+-2x4;5=+-√2x^5 - 3x^3 + x^2 - 3 = 0x^3(x^2-3)+x^2-3=0(x^2-3)(x^3+1)=0x1;2=+-√3   x3=-1 ...