X^2-5=(x-5)(2x-1) (3x-1)^2=1 (x+3)(x-4)=-12 (3x-1)^2=4-12x - вопрос №41055392552131213412312412 от nozim21tx 13.01.2021 21:56

Question

Алгебра: X^2-5=(x-5)(2x-1) (3x-1)^2=1 (x+3)(x-4)=-12 (3x-1)^2=4-12x нужно решить

nozim21tx · Answer

X² - 5 = ( x - 5)(2x - 1)x² - 5 = 2x² - x - 10x + 5x² - 2x² + x + 10x = 5 + 5- x² + 11x - 10 = 0x² - 11x + 10 = 0D = b² - 4ac = ( - 11)² - 4 × 1 × 10 = 121 - 40 = 81 = 9²x₁ = 11 + 9 / 2 = 10x₂ = 11 -9 / 2 = 1( 3x - 1)² = 1( 3x - 1)( 3x - 1) = 19x² - 3x - 3x + 1 - 1 = 09x² - 6x + 0 = 0D = b² - 4ac = 36 - 4 × 9 × 0 = 36 = 6²x₁ = 6 + 6 / 18 = 12/18 = 6/9 = 2/3x₂ = 6 - 6 / 18 = 0( x + 3)( x - 4) = -12x² - 4x + 3x - 12 = - 12x² - x - 12 + 12 = 0x² - x + 0 = 0D = b² - 4ac = 1 - 4 × 1 × 0 = 1 = 1²x₁ =...