Заранее ! преобразуйте выражение в произведение: а) cos; б) ; в)

A) [2cos(2π/3 + π/6)/2] * [cos(2π/3 - π/6)/2] = 2cos(5π/12) * cos(π/4)
б) [2cos(3π/10 + π/10)/2] * [sin(3π/10  - π/10)/2] =
= 2cos(π/5) * sin(π/10)
в) cosβ - cos6β = [2sin(β + 6β)/2 * sin(6β - β)/2] = 
= 2sin (7β/2) * sin(5β/2)]