Надо решить уравнения 1)3х²-7х-40=0 2) х²-4х+3=0

1) 3x^2 - 7x - 40 =0
   D = √49 - (-40 * 3 * 4) =√529 = 23
   x1 = (7+23) / 6 = 5
   x2 = (7-23) / 6 = 8/3
2) x^2 - 4x + 3 = 0
   D = √16 - (3 * 1 * 4) = √4 = 2
   x1 = (4+2) / 2 = 3
   x2 = (4-2) / 2 = 1