Нужна ! (cos^2(2x+п/6)-3/4)(sin(x/2))=0

(cos(2x+π/6)-√3/2)(cos(2x+π/6)+√3/2)sin(x/2)=0
1)cos(2x+π/6)=√3/2
2x+π/6=π/6+2πn U 2x+π/6=-π/6+2πn
2x=2πn U 2x=-π/3+2πn
x=πn U x=-π/6+πn
2)cos(2x+π/6)=-√3/2
2x+π/6=5π/6+2πn U 2x+π/6=-5π/6+2πn
2x=2π/3+2πn U 2x=-π+2πn
x=π/3+πn U x=-π/2+πn
3)sin(x/2)=0
x/2=πn
x=2πn
ответ x=+-π/3+πn, x=πn U x=-π/2+πn