1-sin^6α-cos^6α / 1-sin^4α-cos^4α=sin^2acos^2a/(1-((sin^2a+cos^2a)^2-2sin^2acos^2a))=
=sin^2acos^2a/2sin^2acos^2a=1/2
ответ:-5*cos(alpha)^4+5*cos(alpha)^2-1
1-sin^6α-cos^6α / 1-sin^4α-cos^4α=sin^2acos^2a/(1-((sin^2a+cos^2a)^2-2sin^2acos^2a))=
=sin^2acos^2a/2sin^2acos^2a=1/2
ответ:-5*cos(alpha)^4+5*cos(alpha)^2-1