Решите ! (3x+x²)²-x²(x-5)*(x+5)+2x(8-3x²)= - вопрос №2719091355283 от ianna9227p00tfn 18.08.2021 22:09

Question

Алгебра: Решите ! (3x+x²)²-x²(x-5)*(x+5)+2x(8-3x²)=

ianna9227p00tfn · Answer

(3х+х^2)^2-х^2(х-5)(х+5)+2х(8-3х^2) = 9х²+6х³+х⁴-х²(х²-25)+16х-6х³=9х²+х⁴-х⁴+25х²+16х=34х²+16х
1) 9x^2 + 6x^3 + x^4 - x^2(x - 5)(x + 5) + 2x(8 - 3x^2)
2) 9x^2 + 6x^3 + x^4 - (x^3 - 5x^2)(x+5) + (16x - 6x^3)
3) 9x^2 + 6x^3 + x^4 - (x^4 - 25x^2) + (16x - 6x^3)
4) 9x^2 + 6x^3 + x^4 - x^4 + 25x^2 + 16x - 6x^3
5) 34x^2 + 6x^3 + x^4 - x^4 + 16x - 6x^3
6) 34x^2 + 16x
ответ: 34x^2 + 16x