1)4*3×₊₂+5*3×-7*3×₊₁=20 2)5×₊₁+5×+5*5×₋₁=155 - вопрос №262812014353732025555155 от isaevshamil0535 04.02.2020 20:13

Question

Алгебра: 1)4*3×₊₂+5*3×-7*3×₊₁=20 2)5×₊₁+5×+5*5×₋₁=155

isaevshamil0535 · Answer

1) 4*3×₊₂ + 5*3× - 7*3×₊₁ = 20
   4*3×* 3² + 5*3× - 7*3×* 3 = 20
   36*3× + 5*3× - 21*3× = 20
      (36 + 5 - 21) *3× = 20
   20 *3× = 20
3× = 1
3× = 3^0 ( три в степени 0)
   × = 0