1)
(x-3)(x²+3x+9)-(3x-17)=x³-12
x³-27-3x+17=x³-12
x³-10-3x=x³-12
x³-3x-x³=10-12
-3x=-2
x=2/3
2)
5x-(4-2x+x²)(x+2)+x(x-1)(x+1)=0
5x-(8+x³)+x(x²-1)=0
5x-8-x³+x³-x=0
4x=8
x=2
1)
(x-3)(x²+3x+9)-(3x-17)=x³-12
x³-27-3x+17=x³-12
x³-10-3x=x³-12
x³-3x-x³=10-12
-3x=-2
x=2/3
2)
5x-(4-2x+x²)(x+2)+x(x-1)(x+1)=0
5x-(8+x³)+x(x²-1)=0
5x-8-x³+x³-x=0
4x=8
x=2