Решите мне (a+b)^3= (a-b)^3= (a^3+b^3)= (a^3-b^3)= sin(α+β)= sin(α-β)=

(a+b)^3=a^3+3a^2b+3b^2a+b^3
(a-b)^3=a^3-3a^2b+3ab^2-b^3
(a^3+b^3)=(a+b)(a^2-ab+b^2)
(a^3-b^3)=(a-b)(a^2+ab+b^2)
sin(α+β)=sinacosb+sinbcosa
sin(α-β)=sinacosb-sinbcosa