501. a) (2x – 5)2 - 1 = 0;6) (4y – 7)2 – (y + 2)2 - вопрос №17000749501252106472220 от УРВ05052001 15.08.2021 23:05

Question

Алгебра: 501. a) (2x – 5)2 - 1 = 0;6) (4y – 7)2 – (y + 2)2 = 0​

УРВ05052001 · Answer

№1(2x – 5)2 - 1 = 0;4x-10-1=04x-11=04x=11x=11:4x=2.75№2(4y – 7)2 – (y + 2)2 = 0​8y-14-2y+4=06y-10=06y=10y=10:6y=1.(6)...

501. a) (2x – 5)2 - 1 = 0;6) (4y – 7)2 – (y + 2)2 = 0​