Решить систему уравнений х-y=4 х^2+2xy+y^2=4

x-y=4

x^2+2xy+y^2=4

х-y=4

y=x-4

x^2+2xy+y^2=4

x^2+2x*(x-4)+(x-4)^2=4

3x^2-8x+x^2-8x+16-4=0

4x^2-16x+12=0

D=(-16)^2-4*4*12=256-192=64

x1=(8-(-16))/(2*4)=24/8=3
x2=(-8-(-16))/(2*4)=8/8=1

х-y=4

3-y=4

y=-1

1-y=4

y=-3