1) (х+3)(х-2)-(х+4)(х-1)=3х; (2х+6)(7-4х)=(2-х)(8х+1)+15. - вопрос №16265069132413267428115 от sholpsholp3owhb3d 01.02.2023 18:10

Question

Алгебра: 1) (х+3)(х-2)-(х+4)(х-1)=3х; (2х+6)(7-4х)=(2-х)(8х+1)+15. позя

sholpsholp3owhb3d · Answer

x= -2/5x= 1Объяснение:(x+3)(x-2) -(x+4)(x-1) =x^2+x-6-x^2-3x+4=-2x-2=3x = 5x=-2 = x=-2/5(2x+6)(7-4x)=-8x^2-10x+42=(2-x)(8x+1)+15=-8x^2+15x+17 = 25x =25 = x=1...