(x+7)(x-5)²=13(x-5)
(x+7)(x-5)²-13(x-5)=0
(х-5)((х+7)(х-5)-13)=0
(х-5)(х²-5х+7x-35-13)=0
(x-5)(x²+2x-48)=0
x-5=0
x=5
x²+2x-48=0
D=b²-4ac
D=2²-4×1×(-48)=4+192=√196=14
x1=-2-14/2 = -16/2 = -8
x2=-2+14/2 = 12/2 = 6
ответ: x=5, x1=-8, x2=6
(x+7)(x-5)²=13(x-5)
(x+7)(x-5)²-13(x-5)=0
(х-5)((х+7)(х-5)-13)=0
(х-5)(х²-5х+7x-35-13)=0
(x-5)(x²+2x-48)=0
x-5=0
x=5
x²+2x-48=0
D=b²-4ac
D=2²-4×1×(-48)=4+192=√196=14
x1=-2-14/2 = -16/2 = -8
x2=-2+14/2 = 12/2 = 6
ответ: x=5, x1=-8, x2=6