(2πn)5+(7π)/30,n∈Z
(2πk)/5+(11π)/30,k∈Z
Объяснение:
-2sin5x - 1 = 0
-2sinx=1
sin5x=-1/2
5x=2πn+(7π)/6,n∈Z or 5x=2πk+(11π)/6,k∈Z
x=(2πn)5+(7π)/30,n∈Z or x=(2πk)/5+(11π)/30,k∈Z
(2πn)5+(7π)/30,n∈Z
(2πk)/5+(11π)/30,k∈Z
Объяснение:
-2sin5x - 1 = 0
-2sinx=1
sin5x=-1/2
5x=2πn+(7π)/6,n∈Z or 5x=2πk+(11π)/6,k∈Z
x=(2πn)5+(7π)/30,n∈Z or x=(2πk)/5+(11π)/30,k∈Z