Произведение корней уравнения (2x + 8)^2 (13х – 39) = 26(4x^2 — 64)(х-3)
равно​

х1= -4  х2=3  х3=12

Объяснение:

(2x + 8)^2 (13х – 39) = 26(4x^2 — 64)(х-3)

(4+32+64)(13x-39) = (104-1664)(х-3)

54-156+416-1248x-832x-2496 = 104-312-1664x+4992

54+260-416x-2496 = 104-312-1664x+4992

+5-8x-48 = 2-6-32x+96

+5-8x-48-2+6+32x-96 = 0

-+11+24x-144 = 0

-+3+8-24x+48x-144 = 0

-(x-3)+8x(x-3)+48(x-3) = 0

-(x-3)(-8x-48) = 0

-(x-3)(-4x-12x-48) = 0

-(x-3)(x(x+4)-12(x-4)) = 0

-(x-3)(x-4)(x-12) = 0

(x-3)(x-4)(x-12) = 0

x-3 = 0

x+4 = 0

x-12 = 0

x =3

x =-4

x =2

=3

= -4

=12