Розкласти на множники, розв'язати до 16.04, алгебра, 8 клас

г) (1-9y²) / (3y²-13+4) = (1+3y)(1-3y) / 3(y-4)(y-1/3) = 3(1/3+y)(1/3-y) / 3(y-4)(y-1/3) = (1/3+y)(1/3-y) / (y-4)(y-1/3)

3y²-13+4 = 0;

D = (-13)²-4*3*4 = 169-48 = 121, √D = 11

y₁ = (13+11) / 2*3 = 24/6 = 4

y₂ = (13-11) / 2*3 = 2/6 = 1/3

Значит: 3y²-13+4 = 3(y-4)(y-1/3)

д) (36a²-12a+1) / (6a²+11a-2) = 36(a-1/6)(a-1/6) / 6(a-1/6)(a+2) = 6(a-1/6) / (a+2)

36a²-12a+1 = 0;

D = (-12)²-4*36*1 = 144-144 = 0, √D = 0

a = 12/(2*36) = 12/72 = 1/6

Значит: 36a²-12a+1  = 36(a-1/6)(a-1/6)

6a²+11a-2 = 0;

D = 11²-4*6*(-2) = 121 + 48 = 169, √D = 13

a₁ = (-11+13) / 2*6 = 2/12 = 1/6

a₂ = (-11-13) / 2*6 = -24/12 = -2

Значит: 6a²+11a-2 = 6(a-1/6)(a+2)