решить один из двух примеров,а в идеале оба

1

(√3 + √2)² = 3 + 2√2*√3 + 2 = 5 + 2√6

0.(1) = 1/9

log(√3+√2) (√3 + √2)² - 2log(1/9) √27 = 2 - log(1/3²) 3³ = 2 + 3/2 = 3.5

2

(7 + 4√3)(7 - 4√3) =  49 - 48 = 1

1/(7 + 4√3) = 7 - 4√3 = 7 - √48

0.2 = 1/5

log(0.2) 1/(7+4√3) + log(5) (5(7 - √48)) = log(1/5)(7 - 4√3) + log(5) 5 + log(7 - √48) = log(5)(1/(7 - √48)) + 1 + log(5)(7 - √48) = 1 + log(5) (7 - √48)/(7 - √48) = 1 + log(5) 1 = 1