3y^2+7y-6 = (y+3)*(3*y-2)
3y^2+7y-6=0D = b2 - 4acD = 49 + 72 = 121 = 11
x1,2 = -b ± √D/2ax1 = -7 + 11/6= 4/6= 2/3x2 = -7 - 11/6 = - 18/6 = -3ответ: x1 = 2/3 ; x2 = -3
3y^2+7y-6=3(y-2/3)(y+3)
3y^2+7y-6 = (y+3)*(3*y-2)
3y^2+7y-6=0
D = b2 - 4ac
D = 49 + 72 = 121 = 11
x1,2 = -b ± √D/2a
x1 = -7 + 11/6= 4/6= 2/3
x2 = -7 - 11/6 = - 18/6 = -3
ответ: x1 = 2/3 ; x2 = -3
3y^2+7y-6=3(y-2/3)(y+3)