[tex]x {}^{2} - 37x + 27 = 0[/tex][tex]x {}^{2} - вопрос №10487256237270221002 от radkov02p08713 18.05.2020 12:26

Question

Алгебра: [tex]x {}^{2} - 37x + 27 = 0[/tex][tex]x {}^{2} - 210x = 0[/tex][tex] - y {}^{2} + y = 0[/tex][tex]x {}^{2} + 41x - 371 = 0[/tex][tex]y {}^{2} - 19 = 0[/tex][tex]3x {}^{2} - 10 = 0[/tex]​

radkov02p08713 · Answer

Решение:~1x²- 37x + 27 = 0D = 1369 - 108 = 1261~2x² - 210x = 0x(x - 210) = 0~3y(-y + 1) = 0~4x² + 41x - 371D = 1681 + 1484 = 3165~5y² - 19 = 0y² = 19y = ±√19~63x² - 10 = 03x² = 10...

​

$x {}^{2} - 37x + 27 = 0$
$x {}^{2} - 210x = 0$
$- y {}^{2} + y = 0$
$x {}^{2} + 41x - 371 = 0$
$y {}^{2} - 19 = 0$
$3x {}^{2} - 10 = 0$