Это выражение
4sin(90+30) * tg(270+30)=
4cos30*(-ctg30)=-4*√3/2 * √3=-6.
4sin(120°)tg(300°)=4sin(90°+30°)tg(120°+180°)=4cos(30°)tg(120°)=
=4cos(30°)tg(90°+30°)=-4cos(30°)ctg(30°)=-4·√3/2·√3=-6
Это выражение
4sin(90+30) * tg(270+30)=
4cos30*(-ctg30)=-4*√3/2 * √3=-6.
4sin(120°)tg(300°)=4sin(90°+30°)tg(120°+180°)=4cos(30°)tg(120°)=
=4cos(30°)tg(90°+30°)=-4cos(30°)ctg(30°)=-4·√3/2·√3=-6